PHP 获取当天是本月的第几周(方法教程):
<?php /** * 获取当天是本月的第几周 * author:xiaochuan */ function get_week(){ # 本月第一天 $oneDay = date('Y-m-01', time()); # 本月天数 $tolDay = date('d', strtotime("$oneDay +1 month -1 day")); # 获取今天的日期 $day = date('d',time()); # 计算本月第一天是周几 $week = date('w',strtotime($oneDay)); # 获取本月第一周有多少天 switch($week){ case 0; $weekDay = 1; break; case 1; $weekDay = 7; break; case 2; $weekDay = 6; break; case 3; $weekDay = 5; break; case 4; $weekDay = 4; break; case 5; $weekDay = 3; break; case 6; $weekDay = 2; break; } # 本月除去第一周剩余的天数 $days = $tolDay - $weekDay; # 本月除了第一周还剩余多少周 $d = ceil($days/7); # 本月第二周的第一天 $w = $weekDay +1; $i = '0'; $d = '2'; for($w;$w<=$tolDay;$w++){ $i++; if($i == '8'){ $i = '1'; $d++; } if($day == $w){ return $d; } } } # 显示当天在本月的第几周 echo get_week(); ?>